Input interpretation
3 mol of N-pentane
Basic properties for 3 mol
mass | 0.216 kg (kilograms) 0.477 lb (pounds) 216 grams molar amount | 3 mol (moles) volume | 346 mL (milliliters) 0.346 L (liters) 346 cm^3 (cubic centimeters) 3.46×10^-4 m^3 (cubic meters) 1.46 cups 11.7 fl oz (fluid ounces) 0.731 pints 0.365 quarts 0.0913 gallons equivalents | 3 eq (equivalents) (at STP)
Thermodynamic properties for 3 mol
enthalpy of hydration | -84.9 kJ (kilojoules) | heat capacity C_p | liquid | 501.6 J/K heat of formation Δ_fH° | gaseous | -440.7 kJ latent heat of vaporization | 85.3 kJ (kilojoules) | latent heat of fusion | 25.2 kJ (kilojoules) |
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Energy vs. temperature for 3 mol
(relative to STP)
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Phase change energies for 3 mol from 25 °C
energy required to heat to boiling point | 5.55 kJ (kilojoules) energy required to convert to vapor | 85.3 kJ (kilojoules) energy required to heat to boiling point and convert to vapor | 90.8 kJ (kilojoules) energy released from cooling to freezing point | 77.6 kJ (kilojoules) energy released from converting to solid | 25.2 kJ (kilojoules) energy released from cooling to freezing point and converting to solid | 103 kJ (kilojoules)
Corresponding quantities
sphere radius | 4.354 cm (centimeters) side of a cube | 7.018 cm (centimeters)
Mass composition for 3 mol
C (carbon) | 0.180 kg (83.2%) H (hydrogen) | 36.290 g (16.8%)
Mass composition for 3 mol
Lewis structure
Draw the Lewis structure of N-pentane. Start by drawing the overall structure of the molecule: Count the total valence electrons of the carbon (n_C, val = 4) and hydrogen (n_H, val = 1) atoms: 5 n_C, val + 12 n_H, val = 32 Calculate the number of electrons needed to completely fill the valence shells for carbon (n_C, full = 8) and hydrogen (n_H, full = 2): 5 n_C, full + 12 n_H, full = 64 Subtracting these two numbers shows that 64 - 32 = 32 bonding electrons are needed. Each bond has two electrons, so the above diagram has all the necessary bonds. There are 16 bonds and hence 32 bonding electrons in the diagram. Lastly, fill in the remaining unbonded electrons on each atom. In total, there remain 32 - 32 = 0 electrons left to draw and the diagram is complete: Answer: | |
Chemical names and formulas
formula | CH_3(CH_2)_3CH_3 Hill formula | C_5H_12 name | N-pentane IUPAC name | pentane
Substance properties
molar mass | 72.15 g/mol phase | liquid (at STP) melting point | -129.67 °C boiling point | 36.06 °C density | 0.6262 g/cm^3 surface tension | 0.016 N/m dynamic viscosity | 2.24×10^-4 Pa s (at 25 °C) odor | gasoline-like odor threshold | 400 ppm
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