HCl + NaVO3 = H2O + Cl2 + NaCl + VOCl2

HCl hydrogen chloride + NaVO_3 sodium metavanadate ⟶ H_2O water + Cl_2 chlorine + NaCl sodium chloride + VOCl_2 vanadyl dichloride

Balance the chemical equation algebraically: HCl + NaVO_3 ⟶ H_2O + Cl_2 + NaCl + VOCl_2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 HCl + c_2 NaVO_3 ⟶ c_3 H_2O + c_4 Cl_2 + c_5 NaCl + c_6 VOCl_2 Set the number of atoms in the reactants equal to the number of atoms in the products for Cl, H, Na, O and V: Cl: | c_1 = 2 c_4 + c_5 + 2 c_6 H: | c_1 = 2 c_3 Na: | c_2 = c_5 O: | 3 c_2 = c_3 + c_6 V: | c_2 = c_6 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_4 = 1 and solve the system of equations for the remaining coefficients: c_1 = 8 c_2 = 2 c_3 = 4 c_4 = 1 c_5 = 2 c_6 = 2 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 8 HCl + 2 NaVO_3 ⟶ 4 H_2O + Cl_2 + 2 NaCl + 2 VOCl_2

+ ⟶ + + +

hydrogen chloride + sodium metavanadate ⟶ water + chlorine + sodium chloride + vanadyl dichloride

K_c = ([H2O]^4 [Cl2] [NaCl]^2 [VOCl2]^2)/([HCl]^8 [NaVO3]^2)

rate = -1/8 (Δ[HCl])/(Δt) = -1/2 (Δ[NaVO3])/(Δt) = 1/4 (Δ[H2O])/(Δt) = (Δ[Cl2])/(Δt) = 1/2 (Δ[NaCl])/(Δt) = 1/2 (Δ[VOCl2])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

| hydrogen chloride | sodium metavanadate | water | chlorine | sodium chloride | vanadyl dichloride formula | HCl | NaVO_3 | H_2O | Cl_2 | NaCl | VOCl_2 Hill formula | ClH | NaO_3V | H_2O | Cl_2 | ClNa | Cl_2OV name | hydrogen chloride | sodium metavanadate | water | chlorine | sodium chloride | vanadyl dichloride IUPAC name | hydrogen chloride | sodium oxido-dioxovanadium | water | molecular chlorine | sodium chloride |