Input interpretation
![diphosphorous tetraiodide](../image_source/b7bf3fc9aacda95f5f6f203faa8ab03f.png)
diphosphorous tetraiodide
Chemical names and formulas
![formula | P_2I_4 Hill formula | I_4P_2 name | diphosphorous tetraiodide IUPAC name | diiodophosphanyl-diiodophosphane alternate names | diiodophosphanyl-diiodo-phosphane | diiodophosphanyl-diiodophosphane | diphosphorus tetraiodide | hypodiphosphorous tetraiodide | phosphorus iodide | tetraiododiphosphine mass fractions | I (iodine) 89.1% | P (phosphorus) 10.9%](../image_source/53d0fce2ffb38abf15ec0c18f7b76851.png)
formula | P_2I_4 Hill formula | I_4P_2 name | diphosphorous tetraiodide IUPAC name | diiodophosphanyl-diiodophosphane alternate names | diiodophosphanyl-diiodo-phosphane | diiodophosphanyl-diiodophosphane | diphosphorus tetraiodide | hypodiphosphorous tetraiodide | phosphorus iodide | tetraiododiphosphine mass fractions | I (iodine) 89.1% | P (phosphorus) 10.9%
Lewis structure
![Draw the Lewis structure of diphosphorous tetraiodide. Start by drawing the overall structure of the molecule: Count the total valence electrons of the iodine (n_I, val = 7) and phosphorus (n_P, val = 5) atoms: 4 n_I, val + 2 n_P, val = 38 Calculate the number of electrons needed to completely fill the valence shells for iodine (n_I, full = 8) and phosphorus (n_P, full = 8): 4 n_I, full + 2 n_P, full = 48 Subtracting these two numbers shows that 48 - 38 = 10 bonding electrons are needed. Each bond has two electrons, so the above diagram has all the necessary bonds. There are 5 bonds and hence 10 bonding electrons in the diagram. Lastly, fill in the remaining unbonded electrons on each atom. In total, there remain 38 - 10 = 28 electrons left to draw: Answer: | |](../image_source/63a6e638b2e539a60b69c358e5669a9c.png)
Draw the Lewis structure of diphosphorous tetraiodide. Start by drawing the overall structure of the molecule: Count the total valence electrons of the iodine (n_I, val = 7) and phosphorus (n_P, val = 5) atoms: 4 n_I, val + 2 n_P, val = 38 Calculate the number of electrons needed to completely fill the valence shells for iodine (n_I, full = 8) and phosphorus (n_P, full = 8): 4 n_I, full + 2 n_P, full = 48 Subtracting these two numbers shows that 48 - 38 = 10 bonding electrons are needed. Each bond has two electrons, so the above diagram has all the necessary bonds. There are 5 bonds and hence 10 bonding electrons in the diagram. Lastly, fill in the remaining unbonded electrons on each atom. In total, there remain 38 - 10 = 28 electrons left to draw: Answer: | |
3D structure
![3D structure](../image_source/5bc1e8fca9b5e6a57b82b78ef99e8ecc.png)
3D structure
Basic properties
![molar mass | 569.5654 g/mol phase | solid (at STP) melting point | 125.5 °C density | 4.178 g/cm^3 solubility in water | insoluble](../image_source/74804ca6736505c7f24b6041d93e5e06.png)
molar mass | 569.5654 g/mol phase | solid (at STP) melting point | 125.5 °C density | 4.178 g/cm^3 solubility in water | insoluble
Units
Solid properties (at STP)
![density | 4.178 g/cm^3](../image_source/f5d44df855fd22e50d3c4bc5b9c9f2b6.png)
density | 4.178 g/cm^3
Units
Chemical identifiers
![CAS number | 13455-00-0 PubChem CID number | 83484 PubChem SID number | 24853077 SMILES identifier | P(P(I)I)(I)I InChI identifier | InChI=1/I4P2/c1-5(2)6(3)4 MDL number | MFCD00011526](../image_source/7959cb6a0f02a465d58d30808ced85f3.png)
CAS number | 13455-00-0 PubChem CID number | 83484 PubChem SID number | 24853077 SMILES identifier | P(P(I)I)(I)I InChI identifier | InChI=1/I4P2/c1-5(2)6(3)4 MDL number | MFCD00011526