Input interpretation
N-propanol | structure diagram
Result
Draw the Lewis structure of N-propanol. Start by drawing the overall structure of the molecule: Count the total valence electrons of the carbon (n_C, val = 4), hydrogen (n_H, val = 1), and oxygen (n_O, val = 6) atoms: 3 n_C, val + 8 n_H, val + n_O, val = 26 Calculate the number of electrons needed to completely fill the valence shells for carbon (n_C, full = 8), hydrogen (n_H, full = 2), and oxygen (n_O, full = 8): 3 n_C, full + 8 n_H, full + n_O, full = 48 Subtracting these two numbers shows that 48 - 26 = 22 bonding electrons are needed. Each bond has two electrons, so the above diagram has all the necessary bonds. There are 11 bonds and hence 22 bonding electrons in the diagram. Lastly, fill in the remaining unbonded electrons on each atom. In total, there remain 26 - 22 = 4 electrons left to draw: Answer: | |