Search

critical pressure of chlorine

Input interpretation

chlorine | critical pressure
chlorine | critical pressure

Result

7.991 MPa (megapascals)
7.991 MPa (megapascals)

Unit conversions

7.991×10^6 Pa (pascals)
7.991×10^6 Pa (pascals)
7.991×10^6 N/m^2 (newtons per square meter)
7.991×10^6 N/m^2 (newtons per square meter)
814.9 tf/m^2 (metric tons-force per square meter)
814.9 tf/m^2 (metric tons-force per square meter)
78.87 atm (atmospheres)  (unit officially deprecated)
78.87 atm (atmospheres) (unit officially deprecated)
79.91 bars
79.91 bars
799.1 dbar (decibars)
799.1 dbar (decibars)
0.07991 kbar (kilobars)
0.07991 kbar (kilobars)
814.9 m WC (meters of water column)
814.9 m WC (meters of water column)
0.8149 km WC (kilometers of water column)
0.8149 km WC (kilometers of water column)
1159 psi (pounds-force per square inch)
1159 psi (pounds-force per square inch)
166900 lbf/ft^2 (pounds-force per square foot)
166900 lbf/ft^2 (pounds-force per square foot)

Comparisons as pressure

 ≈ (0.3 to 1.1) × nozzle pressure of a pressure washer ( 6.9×10^6 to 2.7×10^7 Pa )
≈ (0.3 to 1.1) × nozzle pressure of a pressure washer ( 6.9×10^6 to 2.7×10^7 Pa )
 ≈ 0.8 × pressure exerted by a 45 kg woman wearing stiletto heels ( ≈ 1×10^7 Pa )
≈ 0.8 × pressure exerted by a 45 kg woman wearing stiletto heels ( ≈ 1×10^7 Pa )
 ≈ atmospheric pressure on the surface of Venus ( ≈ 9 MPa )
≈ atmospheric pressure on the surface of Venus ( ≈ 9 MPa )

Corresponding quantity

Depth of water d giving gauge pressure p_e from p_e = ρ_(H_2O)gh:  | 815 meters  | 0.51 miles  | 2673 feet  | (assuming maximum water density ≈ 1000 kg/m^3)
Depth of water d giving gauge pressure p_e from p_e = ρ_(H_2O)gh: | 815 meters | 0.51 miles | 2673 feet | (assuming maximum water density ≈ 1000 kg/m^3)