Input interpretation
sulfuric acid + potassium dichromate + stannous sulfate ⟶ water + potassium sulfate + chromium sulfate + Sn(SO4)2
Balanced equation
Balance the chemical equation algebraically: + + ⟶ + + + Sn(SO4)2 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 + c_3 ⟶ c_4 + c_5 + c_6 + c_7 Sn(SO4)2 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, S, Cr, K and Sn: H: | 2 c_1 = 2 c_4 O: | 4 c_1 + 7 c_2 + 4 c_3 = c_4 + 4 c_5 + 12 c_6 + 8 c_7 S: | c_1 + c_3 = c_5 + 3 c_6 + 2 c_7 Cr: | 2 c_2 = 2 c_6 K: | 2 c_2 = 2 c_5 Sn: | c_3 = c_7 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 7 c_2 = 1 c_3 = 3 c_4 = 7 c_5 = 1 c_6 = 1 c_7 = 3 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 7 + + 3 ⟶ 7 + + + 3 Sn(SO4)2
Structures
+ + ⟶ + + + Sn(SO4)2
Names
sulfuric acid + potassium dichromate + stannous sulfate ⟶ water + potassium sulfate + chromium sulfate + Sn(SO4)2
Chemical names and formulas
| sulfuric acid | potassium dichromate | stannous sulfate | water | potassium sulfate | chromium sulfate | Sn(SO4)2 formula | | | | | | | Sn(SO4)2 Hill formula | H_2O_4S | Cr_2K_2O_7 | O_4SSn | H_2O | K_2O_4S | Cr_2O_12S_3 | O8S2Sn name | sulfuric acid | potassium dichromate | stannous sulfate | water | potassium sulfate | chromium sulfate | IUPAC name | sulfuric acid | dipotassium oxido-(oxido-dioxochromio)oxy-dioxochromium | tin(+2) cation sulfate | water | dipotassium sulfate | chromium(+3) cation trisulfate |