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molecular mass of erbium bromide hexahydrate

Input interpretation

erbium bromide hexahydrate | molecular mass
erbium bromide hexahydrate | molecular mass

Result

Find the molecular mass, m, for erbium bromide hexahydrate: m = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: ErBr_3·6H_2O Use the chemical formula, ErBr_3·6H_2O, to count the number of atoms, N_i, for each element:  | N_i  Br (bromine) | 3  Er (erbium) | 1  H (hydrogen) | 12  O (oxygen) | 6 Look up the atomic mass, m_i, in unified atomic mass units, u, for each element in the periodic table:  | N_i | m_i/u  Br (bromine) | 3 | 79.904  Er (erbium) | 1 | 167.259  H (hydrogen) | 12 | 1.008  O (oxygen) | 6 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molecular mass, m: Answer: |   | | N_i | m_i/u | mass/u  Br (bromine) | 3 | 79.904 | 3 × 79.904 = 239.712  Er (erbium) | 1 | 167.259 | 1 × 167.259 = 167.259  H (hydrogen) | 12 | 1.008 | 12 × 1.008 = 12.096  O (oxygen) | 6 | 15.999 | 6 × 15.999 = 95.994  m = 239.712 u + 167.259 u + 12.096 u + 95.994 u = 515.061 u
Find the molecular mass, m, for erbium bromide hexahydrate: m = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: ErBr_3·6H_2O Use the chemical formula, ErBr_3·6H_2O, to count the number of atoms, N_i, for each element: | N_i Br (bromine) | 3 Er (erbium) | 1 H (hydrogen) | 12 O (oxygen) | 6 Look up the atomic mass, m_i, in unified atomic mass units, u, for each element in the periodic table: | N_i | m_i/u Br (bromine) | 3 | 79.904 Er (erbium) | 1 | 167.259 H (hydrogen) | 12 | 1.008 O (oxygen) | 6 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molecular mass, m: Answer: | | | N_i | m_i/u | mass/u Br (bromine) | 3 | 79.904 | 3 × 79.904 = 239.712 Er (erbium) | 1 | 167.259 | 1 × 167.259 = 167.259 H (hydrogen) | 12 | 1.008 | 12 × 1.008 = 12.096 O (oxygen) | 6 | 15.999 | 6 × 15.999 = 95.994 m = 239.712 u + 167.259 u + 12.096 u + 95.994 u = 515.061 u

Unit conversions

515.06 Da (daltons)
515.06 Da (daltons)
0.51506 kDa (kilodaltons)
0.51506 kDa (kilodaltons)
8.5528×10^-22 grams
8.5528×10^-22 grams
8.5528×10^-25 kg (kilograms)
8.5528×10^-25 kg (kilograms)
515.08 chemical atomic mass units  (unit officially deprecated)
515.08 chemical atomic mass units (unit officially deprecated)
515.22 physical atomic mass units  (unit officially deprecated)
515.22 physical atomic mass units (unit officially deprecated)

Comparisons as mass of molecule

 ≈ 0.71 × molecular mass of fullerene ( ≈ 721 u )
≈ 0.71 × molecular mass of fullerene ( ≈ 721 u )
 ≈ 2.7 × molecular mass of caffeine ( ≈ 194 u )
≈ 2.7 × molecular mass of caffeine ( ≈ 194 u )
 ≈ 8.8 × molecular mass of sodium chloride ( ≈ 58 u )
≈ 8.8 × molecular mass of sodium chloride ( ≈ 58 u )

Corresponding quantities

Relative atomic mass A_r from A_r = m_aN_A/M_u:  | 515
Relative atomic mass A_r from A_r = m_aN_A/M_u: | 515
Molar mass M from M = m_aN_A:  | 515 g/mol (grams per mole)
Molar mass M from M = m_aN_A: | 515 g/mol (grams per mole)
Relative molecular mass M_r from M_r = m_mN_A/M_u:  | 515
Relative molecular mass M_r from M_r = m_mN_A/M_u: | 515
Molar mass M from M = m_mN_A:  | 515 g/mol (grams per mole)
Molar mass M from M = m_mN_A: | 515 g/mol (grams per mole)