Input interpretation
![schultenite | molar mass](../image_source/6a668ec9dc2b949a4b5af9695bedd329.png)
schultenite | molar mass
Result
![Find the molar mass, M, for schultenite: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: PbHAsO_4 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i As (arsenic) | 1 H (hydrogen) | 1 O (oxygen) | 4 Pb (lead) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) As (arsenic) | 1 | 74.921595 H (hydrogen) | 1 | 1.008 O (oxygen) | 4 | 15.999 Pb (lead) | 1 | 207.2 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) As (arsenic) | 1 | 74.921595 | 1 × 74.921595 = 74.921595 H (hydrogen) | 1 | 1.008 | 1 × 1.008 = 1.008 O (oxygen) | 4 | 15.999 | 4 × 15.999 = 63.996 Pb (lead) | 1 | 207.2 | 1 × 207.2 = 207.2 M = 74.921595 g/mol + 1.008 g/mol + 63.996 g/mol + 207.2 g/mol = 347.1 g/mol](../image_source/c46090b5c46108df0a1b6894aefbdecf.png)
Find the molar mass, M, for schultenite: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: PbHAsO_4 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i As (arsenic) | 1 H (hydrogen) | 1 O (oxygen) | 4 Pb (lead) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) As (arsenic) | 1 | 74.921595 H (hydrogen) | 1 | 1.008 O (oxygen) | 4 | 15.999 Pb (lead) | 1 | 207.2 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) As (arsenic) | 1 | 74.921595 | 1 × 74.921595 = 74.921595 H (hydrogen) | 1 | 1.008 | 1 × 1.008 = 1.008 O (oxygen) | 4 | 15.999 | 4 × 15.999 = 63.996 Pb (lead) | 1 | 207.2 | 1 × 207.2 = 207.2 M = 74.921595 g/mol + 1.008 g/mol + 63.996 g/mol + 207.2 g/mol = 347.1 g/mol
Unit conversion
![0.3471 kg/mol (kilograms per mole)](../image_source/1826ebf3cf21b9ff8279f765a6ed5ca5.png)
0.3471 kg/mol (kilograms per mole)
Comparisons
![≈ 0.48 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/8b6140f72b7da5ac542d5fc4d5156d42.png)
≈ 0.48 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 1.8 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/bef9504e76538aa16092125c9948b5bb.png)
≈ 1.8 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 5.9 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/298596e293584662349e2fe80ef350ae.png)
≈ 5.9 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 5.8×10^-22 grams | 5.8×10^-25 kg (kilograms) | 347 u (unified atomic mass units) | 347 Da (daltons)](../image_source/52ebeca2b9eff03f695da1bf544c8158.png)
Mass of a molecule m from m = M/N_A: | 5.8×10^-22 grams | 5.8×10^-25 kg (kilograms) | 347 u (unified atomic mass units) | 347 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 347](../image_source/d16620c286b51341cfbd6d14f1377022.png)
Relative molecular mass M_r from M_r = M_u/M: | 347