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molar mass of diphenyl azidophosphate

Input interpretation

diphenyl azidophosphate | molar mass
diphenyl azidophosphate | molar mass

Result

Find the molar mass, M, for diphenyl azidophosphate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: (C_6H_5O)_2P(O)N_3 Use the chemical formula, (C_6H_5O)_2P(O)N_3, to count the number of atoms, N_i, for each element:  | N_i  C (carbon) | 12  H (hydrogen) | 10  N (nitrogen) | 3  O (oxygen) | 3  P (phosphorus) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table:  | N_i | m_i/g·mol^(-1)  C (carbon) | 12 | 12.011  H (hydrogen) | 10 | 1.008  N (nitrogen) | 3 | 14.007  O (oxygen) | 3 | 15.999  P (phosphorus) | 1 | 30.973761998 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: |   | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1)  C (carbon) | 12 | 12.011 | 12 × 12.011 = 144.132  H (hydrogen) | 10 | 1.008 | 10 × 1.008 = 10.080  N (nitrogen) | 3 | 14.007 | 3 × 14.007 = 42.021  O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997  P (phosphorus) | 1 | 30.973761998 | 1 × 30.973761998 = 30.973761998  M = 144.132 g/mol + 10.080 g/mol + 42.021 g/mol + 47.997 g/mol + 30.973761998 g/mol = 275.204 g/mol
Find the molar mass, M, for diphenyl azidophosphate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: (C_6H_5O)_2P(O)N_3 Use the chemical formula, (C_6H_5O)_2P(O)N_3, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 12 H (hydrogen) | 10 N (nitrogen) | 3 O (oxygen) | 3 P (phosphorus) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 12 | 12.011 H (hydrogen) | 10 | 1.008 N (nitrogen) | 3 | 14.007 O (oxygen) | 3 | 15.999 P (phosphorus) | 1 | 30.973761998 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 12 | 12.011 | 12 × 12.011 = 144.132 H (hydrogen) | 10 | 1.008 | 10 × 1.008 = 10.080 N (nitrogen) | 3 | 14.007 | 3 × 14.007 = 42.021 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 P (phosphorus) | 1 | 30.973761998 | 1 × 30.973761998 = 30.973761998 M = 144.132 g/mol + 10.080 g/mol + 42.021 g/mol + 47.997 g/mol + 30.973761998 g/mol = 275.204 g/mol

Unit conversion

0.2752 kg/mol (kilograms per mole)
0.2752 kg/mol (kilograms per mole)

Comparisons

 ≈ 0.38 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 0.38 × molar mass of fullerene ( ≈ 721 g/mol )
 ≈ 1.4 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 1.4 × molar mass of caffeine ( ≈ 194 g/mol )
 ≈ 4.7 × molar mass of sodium chloride ( ≈ 58 g/mol )
≈ 4.7 × molar mass of sodium chloride ( ≈ 58 g/mol )

Corresponding quantities

Mass of a molecule m from m = M/N_A:  | 4.6×10^-22 grams  | 4.6×10^-25 kg (kilograms)  | 275 u (unified atomic mass units)  | 275 Da (daltons)
Mass of a molecule m from m = M/N_A: | 4.6×10^-22 grams | 4.6×10^-25 kg (kilograms) | 275 u (unified atomic mass units) | 275 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M:  | 275
Relative molecular mass M_r from M_r = M_u/M: | 275