Input interpretation
![diphenyl azidophosphate | molar mass](../image_source/493ac1c07f83b194f71750200c96f480.png)
diphenyl azidophosphate | molar mass
Result
![Find the molar mass, M, for diphenyl azidophosphate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: (C_6H_5O)_2P(O)N_3 Use the chemical formula, (C_6H_5O)_2P(O)N_3, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 12 H (hydrogen) | 10 N (nitrogen) | 3 O (oxygen) | 3 P (phosphorus) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 12 | 12.011 H (hydrogen) | 10 | 1.008 N (nitrogen) | 3 | 14.007 O (oxygen) | 3 | 15.999 P (phosphorus) | 1 | 30.973761998 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 12 | 12.011 | 12 × 12.011 = 144.132 H (hydrogen) | 10 | 1.008 | 10 × 1.008 = 10.080 N (nitrogen) | 3 | 14.007 | 3 × 14.007 = 42.021 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 P (phosphorus) | 1 | 30.973761998 | 1 × 30.973761998 = 30.973761998 M = 144.132 g/mol + 10.080 g/mol + 42.021 g/mol + 47.997 g/mol + 30.973761998 g/mol = 275.204 g/mol](../image_source/60921558d27cadc16577884512c0f4e7.png)
Find the molar mass, M, for diphenyl azidophosphate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: (C_6H_5O)_2P(O)N_3 Use the chemical formula, (C_6H_5O)_2P(O)N_3, to count the number of atoms, N_i, for each element: | N_i C (carbon) | 12 H (hydrogen) | 10 N (nitrogen) | 3 O (oxygen) | 3 P (phosphorus) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 12 | 12.011 H (hydrogen) | 10 | 1.008 N (nitrogen) | 3 | 14.007 O (oxygen) | 3 | 15.999 P (phosphorus) | 1 | 30.973761998 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 12 | 12.011 | 12 × 12.011 = 144.132 H (hydrogen) | 10 | 1.008 | 10 × 1.008 = 10.080 N (nitrogen) | 3 | 14.007 | 3 × 14.007 = 42.021 O (oxygen) | 3 | 15.999 | 3 × 15.999 = 47.997 P (phosphorus) | 1 | 30.973761998 | 1 × 30.973761998 = 30.973761998 M = 144.132 g/mol + 10.080 g/mol + 42.021 g/mol + 47.997 g/mol + 30.973761998 g/mol = 275.204 g/mol
Unit conversion
![0.2752 kg/mol (kilograms per mole)](../image_source/fb6f895da3fa645276b88ba827705cba.png)
0.2752 kg/mol (kilograms per mole)
Comparisons
![≈ 0.38 × molar mass of fullerene ( ≈ 721 g/mol )](../image_source/d8cd09ebf6175586064dac29b0d2ad24.png)
≈ 0.38 × molar mass of fullerene ( ≈ 721 g/mol )
![≈ 1.4 × molar mass of caffeine ( ≈ 194 g/mol )](../image_source/dec136dab43c5c580561e0aa07a32ab0.png)
≈ 1.4 × molar mass of caffeine ( ≈ 194 g/mol )
![≈ 4.7 × molar mass of sodium chloride ( ≈ 58 g/mol )](../image_source/77037e8dce1726b76d6fbbe5bbdcb104.png)
≈ 4.7 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
![Mass of a molecule m from m = M/N_A: | 4.6×10^-22 grams | 4.6×10^-25 kg (kilograms) | 275 u (unified atomic mass units) | 275 Da (daltons)](../image_source/e00241aae8f02b7f09a2310cc127f47d.png)
Mass of a molecule m from m = M/N_A: | 4.6×10^-22 grams | 4.6×10^-25 kg (kilograms) | 275 u (unified atomic mass units) | 275 Da (daltons)
![Relative molecular mass M_r from M_r = M_u/M: | 275](../image_source/e89929454b1623c39adb963398551b5a.png)
Relative molecular mass M_r from M_r = M_u/M: | 275