HNO3 + Cu(OH)2 = H2O + Cu(NO3)2

nitric acid + copper hydroxide ⟶ water + copper(II) nitrate

Balance the chemical equation algebraically: + ⟶ + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 ⟶ c_3 + c_4 Set the number of atoms in the reactants equal to the number of atoms in the products for H, N, O and Cu: H: | c_1 + 2 c_2 = 2 c_3 N: | c_1 = 2 c_4 O: | 3 c_1 + 2 c_2 = c_3 + 6 c_4 Cu: | c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 2 c_2 = 1 c_3 = 2 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 2 + ⟶ 2 +

+ ⟶ +

nitric acid + copper hydroxide ⟶ water + copper(II) nitrate

| nitric acid | copper hydroxide | water | copper(II) nitrate Hill formula | HNO_3 | CuH_2O_2 | H_2O | CuN_2O_6 name | nitric acid | copper hydroxide | water | copper(II) nitrate IUPAC name | nitric acid | copper dihydroxide | water | copper(II) nitrate