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H2SO4 + FeCl2 = H2O + SO2 + FeCl3 + Fe2(SO4)3

Input interpretation

H_2SO_4 sulfuric acid + FeCl_2 iron(II) chloride ⟶ H_2O water + SO_2 sulfur dioxide + FeCl_3 iron(III) chloride + Fe_2(SO_4)_3·xH_2O iron(III) sulfate hydrate
H_2SO_4 sulfuric acid + FeCl_2 iron(II) chloride ⟶ H_2O water + SO_2 sulfur dioxide + FeCl_3 iron(III) chloride + Fe_2(SO_4)_3·xH_2O iron(III) sulfate hydrate

Balanced equation

Balance the chemical equation algebraically: H_2SO_4 + FeCl_2 ⟶ H_2O + SO_2 + FeCl_3 + Fe_2(SO_4)_3·xH_2O Add stoichiometric coefficients, c_i, to the reactants and products: c_1 H_2SO_4 + c_2 FeCl_2 ⟶ c_3 H_2O + c_4 SO_2 + c_5 FeCl_3 + c_6 Fe_2(SO_4)_3·xH_2O Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, S, Cl and Fe: H: | 2 c_1 = 2 c_3 O: | 4 c_1 = c_3 + 2 c_4 + 12 c_6 S: | c_1 = c_4 + 3 c_6 Cl: | 2 c_2 = 3 c_5 Fe: | c_2 = c_5 + 2 c_6 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_6 = 1 and solve the system of equations for the remaining coefficients: c_1 = 6 c_2 = 6 c_3 = 6 c_4 = 3 c_5 = 4 c_6 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 6 H_2SO_4 + 6 FeCl_2 ⟶ 6 H_2O + 3 SO_2 + 4 FeCl_3 + Fe_2(SO_4)_3·xH_2O
Balance the chemical equation algebraically: H_2SO_4 + FeCl_2 ⟶ H_2O + SO_2 + FeCl_3 + Fe_2(SO_4)_3·xH_2O Add stoichiometric coefficients, c_i, to the reactants and products: c_1 H_2SO_4 + c_2 FeCl_2 ⟶ c_3 H_2O + c_4 SO_2 + c_5 FeCl_3 + c_6 Fe_2(SO_4)_3·xH_2O Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, S, Cl and Fe: H: | 2 c_1 = 2 c_3 O: | 4 c_1 = c_3 + 2 c_4 + 12 c_6 S: | c_1 = c_4 + 3 c_6 Cl: | 2 c_2 = 3 c_5 Fe: | c_2 = c_5 + 2 c_6 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_6 = 1 and solve the system of equations for the remaining coefficients: c_1 = 6 c_2 = 6 c_3 = 6 c_4 = 3 c_5 = 4 c_6 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 6 H_2SO_4 + 6 FeCl_2 ⟶ 6 H_2O + 3 SO_2 + 4 FeCl_3 + Fe_2(SO_4)_3·xH_2O

Structures

+ ⟶ + + +
+ ⟶ + + +

Names

sulfuric acid + iron(II) chloride ⟶ water + sulfur dioxide + iron(III) chloride + iron(III) sulfate hydrate
sulfuric acid + iron(II) chloride ⟶ water + sulfur dioxide + iron(III) chloride + iron(III) sulfate hydrate

Equilibrium constant

Construct the equilibrium constant, K, expression for: H_2SO_4 + FeCl_2 ⟶ H_2O + SO_2 + FeCl_3 + Fe_2(SO_4)_3·xH_2O Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 6 H_2SO_4 + 6 FeCl_2 ⟶ 6 H_2O + 3 SO_2 + 4 FeCl_3 + Fe_2(SO_4)_3·xH_2O Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2SO_4 | 6 | -6 FeCl_2 | 6 | -6 H_2O | 6 | 6 SO_2 | 3 | 3 FeCl_3 | 4 | 4 Fe_2(SO_4)_3·xH_2O | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression H_2SO_4 | 6 | -6 | ([H2SO4])^(-6) FeCl_2 | 6 | -6 | ([FeCl2])^(-6) H_2O | 6 | 6 | ([H2O])^6 SO_2 | 3 | 3 | ([SO2])^3 FeCl_3 | 4 | 4 | ([FeCl3])^4 Fe_2(SO_4)_3·xH_2O | 1 | 1 | [Fe2(SO4)3·xH2O] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([H2SO4])^(-6) ([FeCl2])^(-6) ([H2O])^6 ([SO2])^3 ([FeCl3])^4 [Fe2(SO4)3·xH2O] = (([H2O])^6 ([SO2])^3 ([FeCl3])^4 [Fe2(SO4)3·xH2O])/(([H2SO4])^6 ([FeCl2])^6)
Construct the equilibrium constant, K, expression for: H_2SO_4 + FeCl_2 ⟶ H_2O + SO_2 + FeCl_3 + Fe_2(SO_4)_3·xH_2O Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 6 H_2SO_4 + 6 FeCl_2 ⟶ 6 H_2O + 3 SO_2 + 4 FeCl_3 + Fe_2(SO_4)_3·xH_2O Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2SO_4 | 6 | -6 FeCl_2 | 6 | -6 H_2O | 6 | 6 SO_2 | 3 | 3 FeCl_3 | 4 | 4 Fe_2(SO_4)_3·xH_2O | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression H_2SO_4 | 6 | -6 | ([H2SO4])^(-6) FeCl_2 | 6 | -6 | ([FeCl2])^(-6) H_2O | 6 | 6 | ([H2O])^6 SO_2 | 3 | 3 | ([SO2])^3 FeCl_3 | 4 | 4 | ([FeCl3])^4 Fe_2(SO_4)_3·xH_2O | 1 | 1 | [Fe2(SO4)3·xH2O] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([H2SO4])^(-6) ([FeCl2])^(-6) ([H2O])^6 ([SO2])^3 ([FeCl3])^4 [Fe2(SO4)3·xH2O] = (([H2O])^6 ([SO2])^3 ([FeCl3])^4 [Fe2(SO4)3·xH2O])/(([H2SO4])^6 ([FeCl2])^6)

Rate of reaction

Construct the rate of reaction expression for: H_2SO_4 + FeCl_2 ⟶ H_2O + SO_2 + FeCl_3 + Fe_2(SO_4)_3·xH_2O Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 6 H_2SO_4 + 6 FeCl_2 ⟶ 6 H_2O + 3 SO_2 + 4 FeCl_3 + Fe_2(SO_4)_3·xH_2O Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2SO_4 | 6 | -6 FeCl_2 | 6 | -6 H_2O | 6 | 6 SO_2 | 3 | 3 FeCl_3 | 4 | 4 Fe_2(SO_4)_3·xH_2O | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term H_2SO_4 | 6 | -6 | -1/6 (Δ[H2SO4])/(Δt) FeCl_2 | 6 | -6 | -1/6 (Δ[FeCl2])/(Δt) H_2O | 6 | 6 | 1/6 (Δ[H2O])/(Δt) SO_2 | 3 | 3 | 1/3 (Δ[SO2])/(Δt) FeCl_3 | 4 | 4 | 1/4 (Δ[FeCl3])/(Δt) Fe_2(SO_4)_3·xH_2O | 1 | 1 | (Δ[Fe2(SO4)3·xH2O])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/6 (Δ[H2SO4])/(Δt) = -1/6 (Δ[FeCl2])/(Δt) = 1/6 (Δ[H2O])/(Δt) = 1/3 (Δ[SO2])/(Δt) = 1/4 (Δ[FeCl3])/(Δt) = (Δ[Fe2(SO4)3·xH2O])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: H_2SO_4 + FeCl_2 ⟶ H_2O + SO_2 + FeCl_3 + Fe_2(SO_4)_3·xH_2O Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 6 H_2SO_4 + 6 FeCl_2 ⟶ 6 H_2O + 3 SO_2 + 4 FeCl_3 + Fe_2(SO_4)_3·xH_2O Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i H_2SO_4 | 6 | -6 FeCl_2 | 6 | -6 H_2O | 6 | 6 SO_2 | 3 | 3 FeCl_3 | 4 | 4 Fe_2(SO_4)_3·xH_2O | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term H_2SO_4 | 6 | -6 | -1/6 (Δ[H2SO4])/(Δt) FeCl_2 | 6 | -6 | -1/6 (Δ[FeCl2])/(Δt) H_2O | 6 | 6 | 1/6 (Δ[H2O])/(Δt) SO_2 | 3 | 3 | 1/3 (Δ[SO2])/(Δt) FeCl_3 | 4 | 4 | 1/4 (Δ[FeCl3])/(Δt) Fe_2(SO_4)_3·xH_2O | 1 | 1 | (Δ[Fe2(SO4)3·xH2O])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/6 (Δ[H2SO4])/(Δt) = -1/6 (Δ[FeCl2])/(Δt) = 1/6 (Δ[H2O])/(Δt) = 1/3 (Δ[SO2])/(Δt) = 1/4 (Δ[FeCl3])/(Δt) = (Δ[Fe2(SO4)3·xH2O])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

| sulfuric acid | iron(II) chloride | water | sulfur dioxide | iron(III) chloride | iron(III) sulfate hydrate formula | H_2SO_4 | FeCl_2 | H_2O | SO_2 | FeCl_3 | Fe_2(SO_4)_3·xH_2O Hill formula | H_2O_4S | Cl_2Fe | H_2O | O_2S | Cl_3Fe | Fe_2O_12S_3 name | sulfuric acid | iron(II) chloride | water | sulfur dioxide | iron(III) chloride | iron(III) sulfate hydrate IUPAC name | sulfuric acid | dichloroiron | water | sulfur dioxide | trichloroiron | diferric trisulfate
| sulfuric acid | iron(II) chloride | water | sulfur dioxide | iron(III) chloride | iron(III) sulfate hydrate formula | H_2SO_4 | FeCl_2 | H_2O | SO_2 | FeCl_3 | Fe_2(SO_4)_3·xH_2O Hill formula | H_2O_4S | Cl_2Fe | H_2O | O_2S | Cl_3Fe | Fe_2O_12S_3 name | sulfuric acid | iron(II) chloride | water | sulfur dioxide | iron(III) chloride | iron(III) sulfate hydrate IUPAC name | sulfuric acid | dichloroiron | water | sulfur dioxide | trichloroiron | diferric trisulfate

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