Input interpretation
copper(II) oxalate hemihydrate | molar mass
Result
Find the molar mass, M, for copper(II) oxalate hemihydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: CuC_2O_4·0.5H_2O Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 4 Cu (copper) | 2 H (hydrogen) | 2 O (oxygen) | 9 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 4 | 12.011 Cu (copper) | 2 | 63.546 H (hydrogen) | 2 | 1.008 O (oxygen) | 9 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 4 | 12.011 | 4 × 12.011 = 48.044 Cu (copper) | 2 | 63.546 | 2 × 63.546 = 127.092 H (hydrogen) | 2 | 1.008 | 2 × 1.008 = 2.016 O (oxygen) | 9 | 15.999 | 9 × 15.999 = 143.991 M = 48.044 g/mol + 127.092 g/mol + 2.016 g/mol + 143.991 g/mol = 321.143 g/mol
Unit conversion
0.32114 kg/mol (kilograms per mole)
Comparisons
≈ 0.45 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 1.7 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 5.5 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 5.3×10^-22 grams | 5.3×10^-25 kg (kilograms) | 321 u (unified atomic mass units) | 321 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 321