Input interpretation
ferric ammonium oxalate | molar mass
Result
Find the molar mass, M, for ferric ammonium oxalate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: C_6H_12FeN_3O_12 Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 6 Fe (iron) | 1 H (hydrogen) | 12 N (nitrogen) | 3 O (oxygen) | 12 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 6 | 12.011 Fe (iron) | 1 | 55.845 H (hydrogen) | 12 | 1.008 N (nitrogen) | 3 | 14.007 O (oxygen) | 12 | 15.999 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 6 | 12.011 | 6 × 12.011 = 72.066 Fe (iron) | 1 | 55.845 | 1 × 55.845 = 55.845 H (hydrogen) | 12 | 1.008 | 12 × 1.008 = 12.096 N (nitrogen) | 3 | 14.007 | 3 × 14.007 = 42.021 O (oxygen) | 12 | 15.999 | 12 × 15.999 = 191.988 M = 72.066 g/mol + 55.845 g/mol + 12.096 g/mol + 42.021 g/mol + 191.988 g/mol = 374.016 g/mol
Unit conversion
0.37402 kg/mol (kilograms per mole)
Comparisons
≈ 0.52 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 1.9 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 6.4 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 6.2×10^-22 grams | 6.2×10^-25 kg (kilograms) | 374 u (unified atomic mass units) | 374 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 374