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HI + Sc(OH)3 = H2O + ScI3

Input interpretation

HI hydrogen iodide + Sc(OH)_3 scandium hydroxide ⟶ H_2O water + ScI_3 scandium(III) iodide
HI hydrogen iodide + Sc(OH)_3 scandium hydroxide ⟶ H_2O water + ScI_3 scandium(III) iodide

Balanced equation

Balance the chemical equation algebraically: HI + Sc(OH)_3 ⟶ H_2O + ScI_3 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 HI + c_2 Sc(OH)_3 ⟶ c_3 H_2O + c_4 ScI_3 Set the number of atoms in the reactants equal to the number of atoms in the products for H, I, O and Sc: H: | c_1 + 3 c_2 = 2 c_3 I: | c_1 = 3 c_4 O: | 3 c_2 = c_3 Sc: | c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 3 c_2 = 1 c_3 = 3 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: |   | 3 HI + Sc(OH)_3 ⟶ 3 H_2O + ScI_3
Balance the chemical equation algebraically: HI + Sc(OH)_3 ⟶ H_2O + ScI_3 Add stoichiometric coefficients, c_i, to the reactants and products: c_1 HI + c_2 Sc(OH)_3 ⟶ c_3 H_2O + c_4 ScI_3 Set the number of atoms in the reactants equal to the number of atoms in the products for H, I, O and Sc: H: | c_1 + 3 c_2 = 2 c_3 I: | c_1 = 3 c_4 O: | 3 c_2 = c_3 Sc: | c_2 = c_4 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_2 = 1 and solve the system of equations for the remaining coefficients: c_1 = 3 c_2 = 1 c_3 = 3 c_4 = 1 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 3 HI + Sc(OH)_3 ⟶ 3 H_2O + ScI_3

Structures

 + ⟶ +
+ ⟶ +

Names

hydrogen iodide + scandium hydroxide ⟶ water + scandium(III) iodide
hydrogen iodide + scandium hydroxide ⟶ water + scandium(III) iodide

Equilibrium constant

Construct the equilibrium constant, K, expression for: HI + Sc(OH)_3 ⟶ H_2O + ScI_3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 3 HI + Sc(OH)_3 ⟶ 3 H_2O + ScI_3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i HI | 3 | -3 Sc(OH)_3 | 1 | -1 H_2O | 3 | 3 ScI_3 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression HI | 3 | -3 | ([HI])^(-3) Sc(OH)_3 | 1 | -1 | ([Sc(OH)3])^(-1) H_2O | 3 | 3 | ([H2O])^3 ScI_3 | 1 | 1 | [ScI3] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: |   | K_c = ([HI])^(-3) ([Sc(OH)3])^(-1) ([H2O])^3 [ScI3] = (([H2O])^3 [ScI3])/(([HI])^3 [Sc(OH)3])
Construct the equilibrium constant, K, expression for: HI + Sc(OH)_3 ⟶ H_2O + ScI_3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the activity expression for each chemical species. • Use the activity expressions to build the equilibrium constant expression. Write the balanced chemical equation: 3 HI + Sc(OH)_3 ⟶ 3 H_2O + ScI_3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i HI | 3 | -3 Sc(OH)_3 | 1 | -1 H_2O | 3 | 3 ScI_3 | 1 | 1 Assemble the activity expressions accounting for the state of matter and ν_i: chemical species | c_i | ν_i | activity expression HI | 3 | -3 | ([HI])^(-3) Sc(OH)_3 | 1 | -1 | ([Sc(OH)3])^(-1) H_2O | 3 | 3 | ([H2O])^3 ScI_3 | 1 | 1 | [ScI3] The equilibrium constant symbol in the concentration basis is: K_c Mulitply the activity expressions to arrive at the K_c expression: Answer: | | K_c = ([HI])^(-3) ([Sc(OH)3])^(-1) ([H2O])^3 [ScI3] = (([H2O])^3 [ScI3])/(([HI])^3 [Sc(OH)3])

Rate of reaction

Construct the rate of reaction expression for: HI + Sc(OH)_3 ⟶ H_2O + ScI_3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 3 HI + Sc(OH)_3 ⟶ 3 H_2O + ScI_3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i HI | 3 | -3 Sc(OH)_3 | 1 | -1 H_2O | 3 | 3 ScI_3 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term HI | 3 | -3 | -1/3 (Δ[HI])/(Δt) Sc(OH)_3 | 1 | -1 | -(Δ[Sc(OH)3])/(Δt) H_2O | 3 | 3 | 1/3 (Δ[H2O])/(Δt) ScI_3 | 1 | 1 | (Δ[ScI3])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: |   | rate = -1/3 (Δ[HI])/(Δt) = -(Δ[Sc(OH)3])/(Δt) = 1/3 (Δ[H2O])/(Δt) = (Δ[ScI3])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)
Construct the rate of reaction expression for: HI + Sc(OH)_3 ⟶ H_2O + ScI_3 Plan: • Balance the chemical equation. • Determine the stoichiometric numbers. • Assemble the rate term for each chemical species. • Write the rate of reaction expression. Write the balanced chemical equation: 3 HI + Sc(OH)_3 ⟶ 3 H_2O + ScI_3 Assign stoichiometric numbers, ν_i, using the stoichiometric coefficients, c_i, from the balanced chemical equation in the following manner: ν_i = -c_i for reactants and ν_i = c_i for products: chemical species | c_i | ν_i HI | 3 | -3 Sc(OH)_3 | 1 | -1 H_2O | 3 | 3 ScI_3 | 1 | 1 The rate term for each chemical species, B_i, is 1/ν_i(Δ[B_i])/(Δt) where [B_i] is the amount concentration and t is time: chemical species | c_i | ν_i | rate term HI | 3 | -3 | -1/3 (Δ[HI])/(Δt) Sc(OH)_3 | 1 | -1 | -(Δ[Sc(OH)3])/(Δt) H_2O | 3 | 3 | 1/3 (Δ[H2O])/(Δt) ScI_3 | 1 | 1 | (Δ[ScI3])/(Δt) (for infinitesimal rate of change, replace Δ with d) Set the rate terms equal to each other to arrive at the rate expression: Answer: | | rate = -1/3 (Δ[HI])/(Δt) = -(Δ[Sc(OH)3])/(Δt) = 1/3 (Δ[H2O])/(Δt) = (Δ[ScI3])/(Δt) (assuming constant volume and no accumulation of intermediates or side products)

Chemical names and formulas

 | hydrogen iodide | scandium hydroxide | water | scandium(III) iodide formula | HI | Sc(OH)_3 | H_2O | ScI_3 Hill formula | HI | H_3O_3Sc | H_2O | I_3Sc name | hydrogen iodide | scandium hydroxide | water | scandium(III) iodide IUPAC name | hydrogen iodide | scandium(+3) cation trihydroxide | water | triiodoscandium
| hydrogen iodide | scandium hydroxide | water | scandium(III) iodide formula | HI | Sc(OH)_3 | H_2O | ScI_3 Hill formula | HI | H_3O_3Sc | H_2O | I_3Sc name | hydrogen iodide | scandium hydroxide | water | scandium(III) iodide IUPAC name | hydrogen iodide | scandium(+3) cation trihydroxide | water | triiodoscandium

Substance properties

 | hydrogen iodide | scandium hydroxide | water | scandium(III) iodide molar mass | 127.912 g/mol | 95.977 g/mol | 18.015 g/mol | 425.66932 g/mol phase | gas (at STP) | | liquid (at STP) | solid (at STP) melting point | -50.76 °C | | 0 °C | 920 °C boiling point | -35.55 °C | | 99.9839 °C |  density | 0.005228 g/cm^3 (at 25 °C) | | 1 g/cm^3 |  solubility in water | very soluble | | |  surface tension | | | 0.0728 N/m |  dynamic viscosity | 0.001321 Pa s (at -39 °C) | | 8.9×10^-4 Pa s (at 25 °C) |  odor | | | odorless |
| hydrogen iodide | scandium hydroxide | water | scandium(III) iodide molar mass | 127.912 g/mol | 95.977 g/mol | 18.015 g/mol | 425.66932 g/mol phase | gas (at STP) | | liquid (at STP) | solid (at STP) melting point | -50.76 °C | | 0 °C | 920 °C boiling point | -35.55 °C | | 99.9839 °C | density | 0.005228 g/cm^3 (at 25 °C) | | 1 g/cm^3 | solubility in water | very soluble | | | surface tension | | | 0.0728 N/m | dynamic viscosity | 0.001321 Pa s (at -39 °C) | | 8.9×10^-4 Pa s (at 25 °C) | odor | | | odorless |

Units