Input interpretation
convert 12 kg of iodine (chemical element) to volume
Results
2.429 L (liters)
Possible intermediate steps
Convert from kilograms into liters: 12 kg of I (iodine) Convert from kilograms to cubic centimeters using the relation 1000 g (grams) = 1 kg (kilogram) and the density 4.94 g/cm^3 (grams per cubic centimeter) at STP of I: (12 kg)/1 × (1000 g)/(1 kg) × (1 cm^3)/(4.94 g) = 2429 cm^3 Convert to milliliters using the relation 1 cm^3 (cubic centimeter) = 1 mL (milliliter): (2429 cm^3)/1 × (1 mL)/(1 cm^3) = 2429 mL Convert to liters using the relation 1000 mL (milliliters) = 1 L (liter): Answer: | | (2429 mL)/1 × (1 L)/(1000 mL) = 2.429 L
Unit conversions
0.002429 m^3 (cubic meters)
2429 cm^3 (cubic centimeters)
82.14 fl oz (fluid ounces)
5.134 pints
2.567 quarts
0.6417 gallons
0.08578 ft^3 (cubic feet)
148.2 in^3 (cubic inches)
Comparisons as volume
≈ ( 0.11 ≈ 1/9 ) × volume of one mole of ideal gas at 273.15 K and 101.325 kPa ( 0.02241 m^3 )
≈ 0.5 × volume of blood in a typical human ( ≈ 5 L )
≈ 0.57 × volume of a American NFL football ( ≈ 259 in^3 )
Comparisons as volume of food or beverage
≈ 0.78 × volume of a US size 10 can ( 105 fl oz )
≈ 1.5 × volume of a US size 5 can ( 7 cups )
≈ 2.6 × volume of a US size 3 can ( 4 cups )
Interpretations
volume
volume of food or beverage
capacity
section modulus
Basic unit dimensions
![[length]^3](../image_source/959636b5033e15dd4684851443a96ed3.png)
[length]^3
Corresponding quantities
Radius r of a sphere from V = 4πr^3/3: | 83 mm (millimeters) | 0.27 feet | 3.3 inches
Edge length a of a cube from V = a^3: | 13 cm (centimeters) | 0.44 feet | 5.3 inches
Mass m of water from m = ρ_(H_2O)V: | 2.4 kg (kilograms) | 5.4 lb (pounds) | (assuming maximum water density ≈ 1000 kg/m^3)
Molecule number N of water from N = ρ_(H_2O)V/m_(H_2O): | 8.12×10^25 molecules | (assuming maximum water density ≈ 1000 kg/m^3) | (assuming molecular mass of water ≈ 18.02 u)