#### Input interpretation

nitric acid + iron ⟶ water + ammonium nitrate + iron(II) nitrate

#### Balanced equation

Balance the chemical equation algebraically: + ⟶ + + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 ⟶ c_3 + c_4 + c_5 Set the number of atoms in the reactants equal to the number of atoms in the products for H, N, O and Fe: H: | c_1 = 2 c_3 + 4 c_4 N: | c_1 = 2 c_4 + 2 c_5 O: | 3 c_1 = c_3 + 3 c_4 + 6 c_5 Fe: | c_2 = c_5 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_4 = 1 and solve the system of equations for the remaining coefficients: c_1 = 10 c_2 = 4 c_3 = 3 c_4 = 1 c_5 = 4 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 10 + 4 ⟶ 3 + + 4

#### Structures

+ ⟶ + +

#### Names

nitric acid + iron ⟶ water + ammonium nitrate + iron(II) nitrate

#### Chemical names and formulas

| nitric acid | iron | water | ammonium nitrate | iron(II) nitrate Hill formula | HNO_3 | Fe | H_2O | H_4N_2O_3 | FeN_2O_6 name | nitric acid | iron | water | ammonium nitrate | iron(II) nitrate