Input interpretation
![sulfuric acid + potassium permanganate + acetic acid ⟶ water + carbon dioxide + potassium sulfate + manganese(II) sulfate](../image_source/090ce795beb18b5ecd44237332f924fe.png)
sulfuric acid + potassium permanganate + acetic acid ⟶ water + carbon dioxide + potassium sulfate + manganese(II) sulfate
Balanced equation
![Balance the chemical equation algebraically: + + ⟶ + + + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 + c_3 ⟶ c_4 + c_5 + c_6 + c_7 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, S, K, Mn and C: H: | 2 c_1 + 4 c_3 = 2 c_4 O: | 4 c_1 + 4 c_2 + 2 c_3 = c_4 + 2 c_5 + 4 c_6 + 4 c_7 S: | c_1 = c_6 + c_7 K: | c_2 = 2 c_6 Mn: | c_2 = c_7 C: | 2 c_3 = c_5 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_6 = 1 and solve the system of equations for the remaining coefficients: c_1 = 3 c_2 = 2 c_3 = 5/4 c_4 = 11/2 c_5 = 5/2 c_6 = 1 c_7 = 2 Multiply by the least common denominator, 4, to eliminate fractional coefficients: c_1 = 12 c_2 = 8 c_3 = 5 c_4 = 22 c_5 = 10 c_6 = 4 c_7 = 8 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 12 + 8 + 5 ⟶ 22 + 10 + 4 + 8](../image_source/349c709b3aae384a47d7d50a79f4ab0b.png)
Balance the chemical equation algebraically: + + ⟶ + + + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 + c_3 ⟶ c_4 + c_5 + c_6 + c_7 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, S, K, Mn and C: H: | 2 c_1 + 4 c_3 = 2 c_4 O: | 4 c_1 + 4 c_2 + 2 c_3 = c_4 + 2 c_5 + 4 c_6 + 4 c_7 S: | c_1 = c_6 + c_7 K: | c_2 = 2 c_6 Mn: | c_2 = c_7 C: | 2 c_3 = c_5 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_6 = 1 and solve the system of equations for the remaining coefficients: c_1 = 3 c_2 = 2 c_3 = 5/4 c_4 = 11/2 c_5 = 5/2 c_6 = 1 c_7 = 2 Multiply by the least common denominator, 4, to eliminate fractional coefficients: c_1 = 12 c_2 = 8 c_3 = 5 c_4 = 22 c_5 = 10 c_6 = 4 c_7 = 8 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 12 + 8 + 5 ⟶ 22 + 10 + 4 + 8
Structures
![+ + ⟶ + + +](../image_source/6ac514d6129785f00f69bb51b14c0e68.png)
+ + ⟶ + + +
Names
![sulfuric acid + potassium permanganate + acetic acid ⟶ water + carbon dioxide + potassium sulfate + manganese(II) sulfate](../image_source/3df3ddd34e8635e103821b32b259bb41.png)
sulfuric acid + potassium permanganate + acetic acid ⟶ water + carbon dioxide + potassium sulfate + manganese(II) sulfate
Chemical names and formulas
![| sulfuric acid | potassium permanganate | acetic acid | water | carbon dioxide | potassium sulfate | manganese(II) sulfate Hill formula | H_2O_4S | KMnO_4 | C_2H_4O_2 | H_2O | CO_2 | K_2O_4S | MnO_4S name | sulfuric acid | potassium permanganate | acetic acid | water | carbon dioxide | potassium sulfate | manganese(II) sulfate IUPAC name | sulfuric acid | potassium permanganate | acetic acid | water | carbon dioxide | dipotassium sulfate | manganese(+2) cation sulfate](../image_source/b1c47d6f219b437b8d2fff7da1ade9cc.png)
| sulfuric acid | potassium permanganate | acetic acid | water | carbon dioxide | potassium sulfate | manganese(II) sulfate Hill formula | H_2O_4S | KMnO_4 | C_2H_4O_2 | H_2O | CO_2 | K_2O_4S | MnO_4S name | sulfuric acid | potassium permanganate | acetic acid | water | carbon dioxide | potassium sulfate | manganese(II) sulfate IUPAC name | sulfuric acid | potassium permanganate | acetic acid | water | carbon dioxide | dipotassium sulfate | manganese(+2) cation sulfate