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H2SO4 + KMnO4 + CH3COOH = H2O + CO2 + K2SO4 + MnSO4

Input interpretation

sulfuric acid + potassium permanganate + acetic acid ⟶ water + carbon dioxide + potassium sulfate + manganese(II) sulfate
sulfuric acid + potassium permanganate + acetic acid ⟶ water + carbon dioxide + potassium sulfate + manganese(II) sulfate

Balanced equation

Balance the chemical equation algebraically:  + + ⟶ + + +  Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 + c_3 ⟶ c_4 + c_5 + c_6 + c_7  Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, S, K, Mn and C: H: | 2 c_1 + 4 c_3 = 2 c_4 O: | 4 c_1 + 4 c_2 + 2 c_3 = c_4 + 2 c_5 + 4 c_6 + 4 c_7 S: | c_1 = c_6 + c_7 K: | c_2 = 2 c_6 Mn: | c_2 = c_7 C: | 2 c_3 = c_5 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_6 = 1 and solve the system of equations for the remaining coefficients: c_1 = 3 c_2 = 2 c_3 = 5/4 c_4 = 11/2 c_5 = 5/2 c_6 = 1 c_7 = 2 Multiply by the least common denominator, 4, to eliminate fractional coefficients: c_1 = 12 c_2 = 8 c_3 = 5 c_4 = 22 c_5 = 10 c_6 = 4 c_7 = 8 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: |   | 12 + 8 + 5 ⟶ 22 + 10 + 4 + 8
Balance the chemical equation algebraically: + + ⟶ + + + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 + c_3 ⟶ c_4 + c_5 + c_6 + c_7 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, S, K, Mn and C: H: | 2 c_1 + 4 c_3 = 2 c_4 O: | 4 c_1 + 4 c_2 + 2 c_3 = c_4 + 2 c_5 + 4 c_6 + 4 c_7 S: | c_1 = c_6 + c_7 K: | c_2 = 2 c_6 Mn: | c_2 = c_7 C: | 2 c_3 = c_5 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_6 = 1 and solve the system of equations for the remaining coefficients: c_1 = 3 c_2 = 2 c_3 = 5/4 c_4 = 11/2 c_5 = 5/2 c_6 = 1 c_7 = 2 Multiply by the least common denominator, 4, to eliminate fractional coefficients: c_1 = 12 c_2 = 8 c_3 = 5 c_4 = 22 c_5 = 10 c_6 = 4 c_7 = 8 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 12 + 8 + 5 ⟶ 22 + 10 + 4 + 8

Structures

 + + ⟶ + + +
+ + ⟶ + + +

Names

sulfuric acid + potassium permanganate + acetic acid ⟶ water + carbon dioxide + potassium sulfate + manganese(II) sulfate
sulfuric acid + potassium permanganate + acetic acid ⟶ water + carbon dioxide + potassium sulfate + manganese(II) sulfate

Chemical names and formulas

 | sulfuric acid | potassium permanganate | acetic acid | water | carbon dioxide | potassium sulfate | manganese(II) sulfate Hill formula | H_2O_4S | KMnO_4 | C_2H_4O_2 | H_2O | CO_2 | K_2O_4S | MnO_4S name | sulfuric acid | potassium permanganate | acetic acid | water | carbon dioxide | potassium sulfate | manganese(II) sulfate IUPAC name | sulfuric acid | potassium permanganate | acetic acid | water | carbon dioxide | dipotassium sulfate | manganese(+2) cation sulfate
| sulfuric acid | potassium permanganate | acetic acid | water | carbon dioxide | potassium sulfate | manganese(II) sulfate Hill formula | H_2O_4S | KMnO_4 | C_2H_4O_2 | H_2O | CO_2 | K_2O_4S | MnO_4S name | sulfuric acid | potassium permanganate | acetic acid | water | carbon dioxide | potassium sulfate | manganese(II) sulfate IUPAC name | sulfuric acid | potassium permanganate | acetic acid | water | carbon dioxide | dipotassium sulfate | manganese(+2) cation sulfate