Input interpretation
zinc formate dihydrate | molar mass
Result
Find the molar mass, M, for zinc formate dihydrate: M = sum _iN_im_i Plan: • Write the chemical formula and gather atomic masses from the periodic table. • Determine values for N_i and m_i using these items. • Finally, compute the mass. Write the chemical formula: Zn(CHO_2)_2·2H_2O Use the chemical formula to count the number of atoms, N_i, for each element: | N_i C (carbon) | 2 H (hydrogen) | 6 O (oxygen) | 6 Zn (zinc) | 1 Look up the atomic mass, m_i, in g·mol^(-1) for each element in the periodic table: | N_i | m_i/g·mol^(-1) C (carbon) | 2 | 12.011 H (hydrogen) | 6 | 1.008 O (oxygen) | 6 | 15.999 Zn (zinc) | 1 | 65.38 Multiply N_i by m_i to compute the mass for each element. Then sum those values to compute the molar mass, M: Answer: | | | N_i | m_i/g·mol^(-1) | mass/g·mol^(-1) C (carbon) | 2 | 12.011 | 2 × 12.011 = 24.022 H (hydrogen) | 6 | 1.008 | 6 × 1.008 = 6.048 O (oxygen) | 6 | 15.999 | 6 × 15.999 = 95.994 Zn (zinc) | 1 | 65.38 | 1 × 65.38 = 65.38 M = 24.022 g/mol + 6.048 g/mol + 95.994 g/mol + 65.38 g/mol = 191.44 g/mol
Unit conversion
0.1914 kg/mol (kilograms per mole)
Comparisons
≈ 0.27 × molar mass of fullerene ( ≈ 721 g/mol )
≈ 0.99 × molar mass of caffeine ( ≈ 194 g/mol )
≈ 3.3 × molar mass of sodium chloride ( ≈ 58 g/mol )
Corresponding quantities
Mass of a molecule m from m = M/N_A: | 3.2×10^-22 grams | 3.2×10^-25 kg (kilograms) | 191 u (unified atomic mass units) | 191 Da (daltons)
Relative molecular mass M_r from M_r = M_u/M: | 191