Input interpretation
![sulfuric acid + sodium nitrite + sodium bichromate ⟶ water + sodium sulfate + chromium sulfate + sodium nitrate](../image_source/d8bf7974d258ef1e80bf7b3eced4ac65.png)
sulfuric acid + sodium nitrite + sodium bichromate ⟶ water + sodium sulfate + chromium sulfate + sodium nitrate
Balanced equation
![Balance the chemical equation algebraically: + + ⟶ + + + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 + c_3 ⟶ c_4 + c_5 + c_6 + c_7 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, S, N, Na and Cr: H: | 2 c_1 = 2 c_4 O: | 4 c_1 + 2 c_2 + 7 c_3 = c_4 + 4 c_5 + 12 c_6 + 3 c_7 S: | c_1 = c_5 + 3 c_6 N: | c_2 = c_7 Na: | c_2 + 2 c_3 = 2 c_5 + c_7 Cr: | 2 c_3 = 2 c_6 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_3 = 1 and solve the system of equations for the remaining coefficients: c_1 = 4 c_2 = 3 c_3 = 1 c_4 = 4 c_5 = 1 c_6 = 1 c_7 = 3 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 4 + 3 + ⟶ 4 + + + 3](../image_source/6dd4324719f7e6612ae09013db6d99b5.png)
Balance the chemical equation algebraically: + + ⟶ + + + Add stoichiometric coefficients, c_i, to the reactants and products: c_1 + c_2 + c_3 ⟶ c_4 + c_5 + c_6 + c_7 Set the number of atoms in the reactants equal to the number of atoms in the products for H, O, S, N, Na and Cr: H: | 2 c_1 = 2 c_4 O: | 4 c_1 + 2 c_2 + 7 c_3 = c_4 + 4 c_5 + 12 c_6 + 3 c_7 S: | c_1 = c_5 + 3 c_6 N: | c_2 = c_7 Na: | c_2 + 2 c_3 = 2 c_5 + c_7 Cr: | 2 c_3 = 2 c_6 Since the coefficients are relative quantities and underdetermined, choose a coefficient to set arbitrarily. To keep the coefficients small, the arbitrary value is ordinarily one. For instance, set c_3 = 1 and solve the system of equations for the remaining coefficients: c_1 = 4 c_2 = 3 c_3 = 1 c_4 = 4 c_5 = 1 c_6 = 1 c_7 = 3 Substitute the coefficients into the chemical reaction to obtain the balanced equation: Answer: | | 4 + 3 + ⟶ 4 + + + 3
Structures
![+ + ⟶ + + +](../image_source/51b8432aca5d1d8980943960507c14d0.png)
+ + ⟶ + + +
Names
![sulfuric acid + sodium nitrite + sodium bichromate ⟶ water + sodium sulfate + chromium sulfate + sodium nitrate](../image_source/34b5d42d3a0ad02b0ea3557f9451dc54.png)
sulfuric acid + sodium nitrite + sodium bichromate ⟶ water + sodium sulfate + chromium sulfate + sodium nitrate
Chemical names and formulas
![| sulfuric acid | sodium nitrite | sodium bichromate | water | sodium sulfate | chromium sulfate | sodium nitrate Hill formula | H_2O_4S | NNaO_2 | Cr_2Na_2O_7 | H_2O | Na_2O_4S | Cr_2O_12S_3 | NNaO_3 name | sulfuric acid | sodium nitrite | sodium bichromate | water | sodium sulfate | chromium sulfate | sodium nitrate IUPAC name | sulfuric acid | sodium nitrite | disodium oxido-(oxido-dioxo-chromio)oxy-dioxo-chromium | water | disodium sulfate | chromium(+3) cation trisulfate | sodium nitrate](../image_source/71e36dd8fd0e2b4e72a817385d1012e2.png)
| sulfuric acid | sodium nitrite | sodium bichromate | water | sodium sulfate | chromium sulfate | sodium nitrate Hill formula | H_2O_4S | NNaO_2 | Cr_2Na_2O_7 | H_2O | Na_2O_4S | Cr_2O_12S_3 | NNaO_3 name | sulfuric acid | sodium nitrite | sodium bichromate | water | sodium sulfate | chromium sulfate | sodium nitrate IUPAC name | sulfuric acid | sodium nitrite | disodium oxido-(oxido-dioxo-chromio)oxy-dioxo-chromium | water | disodium sulfate | chromium(+3) cation trisulfate | sodium nitrate